Showing posts with label percentages. Show all posts
Showing posts with label percentages. Show all posts

Tuesday, June 9, 2015

[Pri20150609PCBA] Members of a New Fitness Club

Question

Introduction
     This is a question on percentages.  Percentages are in themselves also units.  One percent (1%) simply means 1/100.  And we can use units (shown circled in the diagrams below) in which each unit is  1/100  or  1%  of some whole.
     It is useful to think of increases and decreases as multiplying by some percentage.  For example, a decrease by 20%  means multiplying by  100% – 20%  i.e.  80%.  After all, if you work out  100%  of something and subtract  20%  of the same thing,  you will end up with  80%  of that thing.  It is much easier to think of it that way.  Likewise, an increase of  45%  means multiplication by  100% + 45% = 145%.


Solution
     From the information given in the question, we can set up a diagram like this.  I use circles to envelop the percentage units.

We can work out the units in the “after” situation (one year later):-
40 ×  80%  = 40 ×   4/5  = 32
60 × 145% = 60 × 29/20 = 87


The new total is  119%  or  119 circle units.  The net increase is  19%  or  19 circle units, which we know is equivalent to  228.  Once we got this part, we can work out  1  circle unit  and then  20 circle units, which is the difference between the number of male and female members.  [Remember the check that you are answering the question that was asked.]

Ans: 240

Summary
     We have used a diagram in the form of a ratio-units model [H02].  The ratio unit used in this example happens to be the same as a percentage.  Be careful that other questions may involve different kinds of units with different bases for their percentages.  In other words, in other questions, the “100%” may stand for different things.  In the diagram, we have used the before-after concept [H06].  Increases or decreases in percentages may be re-stated as multiplications by the appropriate percentages, which, in turn, may be thought of as multiplications by fractions [H09].  It is a good idea to be able to inter-convert between fractions and percentages.  By comparison, we found the link between  19 units (or 19%)  and  228 [H11].  Having solved this part of the problem, we are able to answer the original question as asked.

H02. Use a diagram / model
H06. Use before-after concept
H09. Restate the problem in another way
H11. Solve part of the problem

Suitable Levels
Primary School Mathematics
* other syllabuses that involve percentages and ratios



Sunday, May 17, 2015

[Pri20150510PEP] Percentages of Erasers and Pens

Question

Introduction
     This is a question about percentages, which are really fractions based upon 100 as denominator.  For example,  60%  just means  60/100.    It is possible to solve this using some sort of algebraic approach based on  100  units for a percentage.  However it is more convenient to use fractions in their lowest terms.  I present a solution based on my Distinguished Units Method, which is a proto-algebraic approach.

Solution
     Note that  60% = 60/100 = 3/5  and  25% = 1/4.  The Lowest Common Multiple (LCM) of the denominators is  20.  I use  20 “square” units for the original number of erasers and  20  “circle” units for the original number of pens.  This makes the units easy to divide.  It does not matter what shape you use to envelop the different units, as long as different shapes are used for different types of units.

          Ans:  There were  240  pens at first.
Since the question asks for the original number of pens, it is a good idea to equalise the eraser’s “square” units.  Multiplying the first row numbers by  8/20  gives 8  “square” units for the third rows.  This serves as a stepping stone to connect the “circle” units.  See the part highlighted in yellow.  From  8  “circle” units to  15  “circle” units, the difference is  84.  This allows us to deduce the value of  1  “circle” unit.  The original number of pens is represented by  20  “circle” units corresponds to  240,  which is the answer we want.


Final Remarks
     It is a good idea to know the fractions of some of the more common percentages.  For example,
     25% = 1/4,   50% = 1/2,   75% = 3/4
     20% = 1/5,   40% = 2/5,   60% = 3/5 ,   80% = 4/5
The usage of  LCM of the denominators is very effective for making calculations easy.

H02. Use a diagram / model
H04. Look for pattern(s)
H06. Use before-after concept
H09. Restate the problem in another way
H10. Simplify the problem
H11. Solve part of the problem

Suitable Levels
Primary School Mathematics

* other syllabuses that involve whole numbers and ratios

Tuesday, January 10, 2012

P6HQ2000S46 Ratio, Proportion and Percentages



Introduction
     This is a challenging question on the topic of ratio, proportion and percentages.  I shall again illustrate the process of solving this mathematics question with metacognition and heuristics, which are applicable for all levels, and all topics.  The Bar Diagram Model is a very well known heuristic.  But there are many other good problem-solving heuristics as well.  There is a key to solving this kind of question and in order not to spoil the fun, I shall let my readers have a go at it first.  Please think a bit about this problem, and then read on.

Stage 1:  Understanding the Problem

Can you explain the problem in your own words?
     Siti paid \$ 24 for some towels at a discount of 20%.  Now, with the discount, she got three more towels than without the discount.

What concepts is this problem testing you on?
     Ratio, proportion, percentages, price, unit price …


Can organise the given information?
     We can put the information into a table, like this:-
Figure 1.  Heuristics: ‘Use a table’ and ‘compare before/after’
What are you asked to find? 

(a) the number (quantity) of towels Siti bought with the discount
(b) the price of each towel (the unit price) before the discount

Stage 2:  Planning the Method of Attack

How are things related?

     Total Price = Quantity (how many she bought) x Unit Price (how much each cost)
This relation is similar to
     Distance = Speed x Time

Have you solved a similar problem before?  How did you solve it the last time?
     Yes, a Distance-Speed-Time problem.  We used a Triangle Mnemonic.
Figure 2.  Triangle Mnemonics and Analogous Thinking


How is this problem different?
     Instead of ‘Distance’, we have ‘Total Price’
     Instead of ‘Speed’, we have ‘Unit Price’
     Instead of ‘Time’, we have ‘Quantity’
     Ah!  Maybe we can use a similar Triangle Mnemonic for Total Price, Unit Price and Quantity.


Remember: What are you trying to find?
     The number of towels - the Quantity.  OK … so … if we use a finger to cover ‘Q’ we see ‘T’ over ‘U’.  That means
     Quantity = Total Price ÷ Unit Price
     But this problem looks more difficult, because there are so many unknowns …

Don’t give up.  Try some heuristics.  (emotional management)

Can you restate the problem in another way?  (using a heuristic)

     The discount of 20% means she paid 100% – 20% = 80% = 4/5 of the original price.  Without the discount, she either would have paid more for the same number of towels, or for the same amount of money, she would have gotten less. …

Can you simplify the problem?  (using a heuristic)
     Suppose the unit price was halved.  Then Siti would get double or 2 times the number of towels.  What if … the unit price was 1/3 of the original?  Then she would get thrice (3 times) the number of towels.  If the price is 1/4 of the original, then she would get 4 times …  It looks like the cheaper the things get, the more you can buy … there is a pattern … the numbers seem to go the opposite way … the fraction seems to be inverted (the reciprocal) … why? … why? … why?  Oh!  It’s because
     Quantity = Total Price ÷ Unit Price


The division ‘÷’ causes the fractions to ‘turn over’.  I see!  J  So, since the price is 4/5 of the original, Siti would have bought  5/4  of the number of towels without discount!


Can you draw a bar diagram for this?  (using the famous Singapore heuristic)
     Yes!
Figure 3. Before-After Comparison Bar Model

Now, can we solve the problem?
     Yes!  Yes!  Yes!  It is now very easy.


Stage 3: Execution
(a)      1 part    =  3 towels  (after discount: 3 more towels)
          5 parts   =  3 ´ 5  = 15 towels

(b)       4 parts =  3 ´ 4 = 12 towels  (before discount)
          12 towels  ¬¾®  \$ 24
              1 towel  ¬¾®  \$  2

Answer:
(a)  She bought 15 towels.
(b)  Before the discount, each towel cost  \$2.



Stage 4:  Evaluation
     Let us check the answer:-
Figure 4.  Checking the answer


     Are we correct?
     Yes!  The numbers fit nicely.

Final Presentation

       The final presentation of the solution can be rather succinct.  The foregoing discussion seems long because all the thinking process are explained in full detail.  The checking of the answers can be done in pencil as rough work.
Figure 5. Final Presentation




Stage 5:  Reflection

What did you learn by solving this problem?

     Although all stages are important, the hardest part was stage 2, the planning stage.  This involves trying various heuristics to look at the problem from different angles.  [This is the real mathematics.  Patience, observation and creativity are needed.]   The key to solving this problem was to note the inverse ratio relationship between quantity and unit price (given a fixed total price).  Once we managed to find the key, we draw the appropriate diagram and the rest of the calculations are pretty straightforward.



In future if you encounter a similar problem, how would you solve it?
     If there is a similar problem in future, I can use the 5 stage problem-solving process:-
     1. Understanding
     2. Planning
     3. Execution
     4. Evaluation
     5. Reflection (learn and transfer for use in future)

Use metacognition (thinking about my own thinking, ask myself questions) to guide myself through the five stages.  Manage my own emotions.  If I get stuck, do not give up.  Look at the problem in different ways.

I can use the following heuristics:-
     · Bar model diagram (yes, but there are others …)
     · drawing a table
     · comparing ‘Before vs After’
     · using a Triangle Mnemonic
     · thinking of a similar problem
     · simplifying the problem
     · rephrasing the problem in another way (e.g. convert percentages to fractions)




Dear blogger: why don’t you just present the answer?

     Many book authors and teachers already do just that.  But do pupils’ actually improve much?  Mathematics still remains a mystery to many pupils.  They think that certain people are born geniuses and that there is always a way that these geniuses somehow have the knack of finding the right steps straightaway (and they themselves cannot).  All they do is try to memorise the algorithm and reproduce it, regardless of whether they understand it.   There is research to show that using worked examples alone does not improve pupils’ mathematics much, and that heuristics and metacognition are actually very important in mathematical problem solving.

     “Give a person a fish; you have fed him/her for today.
       Teach a person to fish; and you have fed him/her for a lifetime”

     If you take the time mimic these heuristic and metacognitive processes, your maths will definitely improve by leaps and bounds.  You still need to know the basic concepts, which most teachers teach, but you need to learn to put them together.   I hope you get empowered in this process.