Question
Introduction
We have
seen here, here and here
that recognising chunks is useful in mathematics. It is an example of a having what Carolyn Kieran
calls a structural view of algebra, which is a type of pattern recognition. In this article, I show how, using chunking
and substitution, we can piggy-back or ride on solutions of a simpler equation
to obtain solutions of a more complicated equation.
The solution
for part (a) of is easy enough. Just factorise (or AmE.
“factor”)
(y
+ 2)(y – 7) = 0
Hence y + 2 = 0 or y – 7 = 0
y = -2 or y = 7
This is Standard Operating Procedure. But part (b) seems like a monster of an
equation. Oh dear! What shall we do?
Observation
Can you observe anything appearing more
than once?
Now
do you notice any chunks that are repeated?
Once you can see the connection, you can make a substitution y =
x3 – 1 and then make use of the answer in part (a). We copy and paste the chunk (shown in green) into
the previous solution and proceed from there.
Solution to part (b)
x3 – 1 = -2 or x3 – 1 = 7
x3
= -1 or x3 = 8
x
= -1 or x = 2
Solved!
H04. Look for pattern(s)
H05. Work backwards
H09. Restate the problem in
another way
H11. Solve part of the problem
H13* Use Equation / write a
Mathematical Sentence
Suitable Levels
* Lower
Secondary Mathematics (Sec 2 ~ Grade 8-9)
* any syllabus that
includes algebraic factorisation (factoring) and substitution
* anyone who is
interested in and ready for algebra
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